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4x+6=x^2+12
We move all terms to the left:
4x+6-(x^2+12)=0
We get rid of parentheses
-x^2+4x-12+6=0
We add all the numbers together, and all the variables
-1x^2+4x-6=0
a = -1; b = 4; c = -6;
Δ = b2-4ac
Δ = 42-4·(-1)·(-6)
Δ = -8
Delta is less than zero, so there is no solution for the equation
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